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Form 1 Mathematics - Order This CD Today

The concept of G.C.D/H.C.F is applicable in many real life situations:

Given two containers of capacity 20 litres and 30 litres respectively. Find the capacity of largest jug that can be used to fill each of containers exactly.

Solution  

20 = 2 x 2 x 5 ,

30 = 2 x 3 x 5

Common factors are 2 and 5

G.C.D = 2 X 5 = 10

Four ribbons of colours red , blue green and yellow of lengths 18m, 24m, 36m and 42 m respectively are to be used for wrapping a number of birthday gifts. The owner wishes to cut them into shorter pieces of equal length. find the greatest possible length if no ribbon is left over.

Solution

Write the numbers 18,24,36 and 42 as a product of their prime factors

18 = 2 x 3 x 3

24 = 2 x 2 x 2 x 3

36 = 2 x 2 x 3 x 3

42= 2 x 3 x 7

The common factors are 2 and 3

The G.C.D is 2 x 3 = 6 . Therefore the greatest possible length is 6m





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